Hey guys, plz help me with my program.

Plz make this program and submit it, I would be very grateful.

Thanks in advance.

 

 

Sort the array in ascending order before counting using JAVA Programming

It should ask user for numbers using array and then arrange in ascending order and count the reapeated number.

Suppose user inputs: 1  4 5 4 4 1

The output should be similar to the following sample output:

                

    

 

            Number       Count                 

                        1                  2

                        4                  3

                        5                  1

.                    .

.                    .

.                    .

Thanks

        

Hey mate,
Problem solved !!!!!!

/* FOR SAJHA MATE */

package sajhabro;

public class Sort {
    public static void main(String[] args) {
        int[] a = new int[] { 1, 4, 5, 4, 4, 1 };
        int temp = 0, count = 1;
//SORTS UNSORTED ARRAY
        for (int i = 0; i < a.length; i++) {
            for (int j = i + 1; j < a.length; j++) {
                if (a[i] > a[j]) {
                    temp = a[i];
                    a[i] = a[j];
                    a[j] = temp;
                }
            }
        }
        System.out.println("Number\t\tCount");
//PRINTS SORTED ARRAY AND COUNTER
        for (int i = 0; i < a.length; i++) {
            for (int j = i + 1; j < a.length; j++) {
                if (a[i] == a[j] && a[j] != '*') {
                    a[j] = '*';
                    count++;
                }
            }
            if (a[i] != '*')
                System.out.println(a[i] + "\t\t" + count);
            count = 1;
        }
    }
}

ganatantranepal has done it pretty nicely, mine looks messsy, this will take 10 input from user

import java.lang.*;
import java.io.*;

 

public class jayNepal {
 
 public static void main(String[] args) throws Exception
 {      
                // Read from console
                
                 BufferedReader stdin = new BufferedReader
                  (new InputStreamReader(System.in));

               int[] a=new int[10];
         for(int i=0;i<10;i++)
  {
   System.out.println("Enter value:");
   String input = stdin.readLine();  // from console input example above.
   a[i] = Integer.parseInt( input ); 
  }

               //Sort 
               for(int i=0;i<10;i++)
                 for(int j=i;j<10;j++)
                     {
                          if(a[i]>a[j])
                              {
                                 int temp=a[i];
                                 a[i]=a[j];
                                 a[j]=temp;
                              }
                      }     
                //Count
                System.out.println("Number\tCount");
                System.out.print(a[0]+"\t");
                int count=1;
                for(int i=1;i<10;i++)
                {
                        if(a[i]==a[i-1])
                        { count++;}
                        else
                        {
                          System.out.print(count +"\n" + a[i]+"\t");
                          count=1;
                        }
                 }
                 System.out.print(count);                      
                         

             }
               
 
}

Hey dude suike
Why are you jealous?
Is it because you didnot get an idea to get help like this and got poor gpa??
sorry for ur gpa....
anyways thanks techguy and ganatantranepal..
i will never forget ur help..
jai nepal

hi DevilWithin999,
I got a linear time (O(n)) solution but it might take a lot of space in worst case.

public class Sort {

    public static void main(String[] args) {
        int[] inputArray = new int[]{1, 4, 5, 4, 4, 1};
       
        //Calculate the maximum length required for bucket array 
        int max = inputArray.length;
        for(int i:inputArray){
            if(i>max){
                max = i;
            }
        }
       
        int bucketArray[] = new int[max];
        for(int i =0;i<inputArray.length;i++){
            bucketArray[inputArray[i]]++;
        }
       
        for(int i = 0;i<bucketArray.length;i++){
            if(bucketArray[i]!=0){
                System.out.println("Number : " + i + " Count: " + bucketArray[i]);
            }
        }

    }
}


Happy Programming.

and the output is:
Number : 1 Count: 2
Number : 4 Count: 3
Number : 5 Count: 1